An irregularly shaped stone was lowered into a gradulated cylinder holding a volume of water equal to 2.0mL.the height of the water rose to 7.0mL if the mass of the stone was 25 what was it's density?(find the difference in the height of the water)

The of the stone is ##”5.0 g/cm”^3##.

The volume of the stone is the difference between the second volume of the water and the first volume.

##”Volume”_”stone”=”7.0 mL”-“2.0 mL=5.0 mL”##

##”Mass”_”stone”=”25 g”##

##”Density”=(“Mass”)/(“Volume”)=”25 g”/”5.0 mL”=”5.0 g/mL”##

##”1 mL”=”1 cm”^3##

The density of the stone is ##”5.0 g/cm”^3##.

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